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题解 | 二分查找-I

/** * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @param target int整型 * @return int整型 * @ 解题的关键在于要记住下标，用递归的话会比较麻烦 */ fu...

2025-08-25

0 7

题解 | 好串

const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...

2025-08-19

0 10

题解 | 好串

const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...

2025-08-19

0 10

题解 | 小苯的IDE括号问题（easy）

const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...

2025-08-19

0 10

题解 | 全排列

const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...

2025-08-15

0 13

题解 | 分数线划定

const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...

2025-08-15

0 15

题解 | 被打乱的异或和

const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...

2025-08-15

0 14

题解 | 多项式输出

const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...

2025-08-15

0 14

题解 | 小红的字符串修改

const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...

2025-08-15

0 17