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题解 | #链表中的节点每k个一组翻转#
最短python递归版本,自解释 class Solution: def reverseKGroup(self , head , k ): t = head for i in range(k): if t is None: ...
python
2021-08-01
3
498
patient sort + 记录前驱位置
class Solution: def LIS(self, arr): stack = [0] n = len(arr) pre = [-1] * n for i in range(1, n): if a...
python
LIS
快手
2021-04-01
3
672