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(共4篇)
题解 | 游戏平台新玩家消费与进阶行为分析
select a.player_id, a.username, a.level as current_level, case when a.level >= 30 then '高阶玩家' else '新秀玩家' end as playe...
2026-01-31
0
10
题解 | SaaS产品高价值用户活跃度分析
select concat(a.user_name, '(', a.user_id, ')' ) as user_profile, b.total_activity_score, round(b.evt_times / 3, 2) as avg_monthly_events ...
2026-01-31
0
10
题解 | 近7天骑手履约时效看板
select courier_id,courier_name,city, orders_7d,on_time_7d,on_time_rate,avg_minutes_7d ,row_number() over(partition by city order by on...
2026-01-10
0
24
题解 | #剩下的树#
#include<bits/stdc++.h> using namespace std; int main() { int m, n; cin >> m >> n; vector<int> v(m + 1, 0); fo...
2024-03-16
0
285