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题解 | #统计每个用户的平均刷题数#

SELECT up.university as university, qd.difficult_level as difficult_level, &...

Mysql

2022-04-13

0 313

题解 | #统计每个学校各难度的用户平均刷题数#

SELECT up.university as university, qd.difficult_level as difficult_level, &...

Mysql

2022-04-13

0 318

题解 | #统计每个学校的答过题的用户的平均答题数#

SELECT u.university as university, count(q.question_id)/count(distinct q.device_id)&nbs...

Mysql

2022-04-13

0 289