ACM模版

描述

题解

简单的模拟问题，一个循环搞定。

代码

#include <iostream>

using namespace std;

const int MAXN = 15;

int n;
int A[MAXN];
int B[MAXN];

int gcd(int a, int b)
{
    return b == 0 ? a : gcd(b, a % b);
}

int main()
{
    int T;
    cin >> T;

    for (int ce = 1; ce <= T; ce++)
    {
        cout << "Case #" << ce << ": ";

        cin >> n;
        for (int i = 1; i <= n; i++)
        {
            cin >> A[i];
        }
        for (int i = 1; i <= n; i++)
        {
            cin >> B[i];
        }

        int p = B[n], q = A[n], t;

        for (int i = n; i > 1; i--)
        {
            p += q * A[i - 1];
            t = p;
            p = B[i - 1] * q;
            q = t;
        }

        t = gcd(p, q);

        cout << p / t << ' ' << q / t << '\n';
    }

    return 0;
}