描述
题解
实际上就是一个建树遍历树的过程,很简单,代码一看就知晓了……水题。不过,算是丰富了一个关于树的知识,原来还有名字这么霸气的一棵树啊!
代码
#include <iostream>
#include <string>
using namespace std;
typedef struct BTNode
{
char state;
int l, r;
BTNode *left, *right;
BTNode(int l_, int r_)
{
l = l_;
r = r_;
left = right = NULL;
}
} *BTree;
BTree root;
string s;
void BuildBTree(BTree &t, int l, int r)
{
t = new BTNode(l, r);
if (l == r)
{
if (s[l] == '0')
{
t->state = 'B';
}
else
{
t->state = 'I';
}
return ;
}
int m = (l + r) >> 1;
BuildBTree(t->left, l, m);
BuildBTree(t->right, m + 1, r);
if (t->left->state == 'I' && t->right->state == 'I')
{
t->state = 'I';
}
else if (t->left->state == 'B' && t->right->state == 'B')
{
t->state = 'B';
}
else
{
t->state = 'F';
}
}
void PrintfBTree(BTree p)
{
if (p != NULL)
{
PrintfBTree(p->left);
PrintfBTree(p->right);
cout << p->state;
}
}
int main(int argc, const char * argv[])
{
int N;
cin >> N;
cin >> s;
BuildBTree(root, 0, (int)s.length() - 1);
PrintfBTree(root);
putchar(10);
return 0;
}
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