ACM模版

题目

代码

#include <iostream>

using namespace std;

int flip(int x)
{
    if (x & 1)
    {
        return x;
    }

    int n = 0;
    while (x)
    {
        n = (n << 1) | (x & 1);
        x >>= 1;
    }

    return n;
}

int N, x;

int main(int argc, const char * argv[])
{
    while (cin >> N)
    {
        for (int i = 0; i < N; i++)
        {
            cin >> x;
            cout << flip(x);
            if (i != N - 1)
            {
                cout << ' ';
            }
            else
            {
                cout << '\n';
            }
        }
    }

    return 0;
}

题目


代码

#include <iostream>
#include <cstring>
#include <cstdio>

using namespace std;

const int MAXN = 6;

int n, ans;
string s[MAXN];
int vis[MAXN];

void dfs(int p)
{
    if (p == n)
    {
        ans++;
        return ;
    }
    for (int i = 0; i < s[p].length(); i++)
    {
        if (vis[s[p][i] - '0'] == 0)
        {
            vis[s[p][i] - '0'] = 1;
            dfs(p + 1);
            vis[s[p][i] - '0'] = 0;
        }
    }
}

int main(int argc, const char * argv[])
{
    while (cin >> n)
    {
        ans = 0;
        memset(vis, 0, sizeof(vis));
        for (int i = 0; i < n; i++)
        {
            cin >> s[i];
        }

        dfs(0);

        cout << ans << endl;
    }

    return 0;
}

题目

代码

#include <iostream>
#include <cmath>

using namespace std;

int a, b;

int main(int argc, const char * argv[])
{
    while (cin >> a >> b)
    {
        int cnt = 0;
        int sta = ceil(a / 0.95);
        int end = floor(a / 0.90);

        while (sta % 5 != 0 && sta <= end)
        {
            sta++;
        }
        for (int i = sta; i <= end && i <= b; i += 5)
        {
            cnt++;
        }

        cout << cnt << endl;
    }

    return 0;
}